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ISO year (numeric) from Date object

Usage

date_to_isoyear_n(x = lubridate::today())

# S3 method for default
date_to_isoyear_n(x)

# S3 method for character
date_to_isoyear_n(x = lubridate::today())

# S3 method for Date
date_to_isoyear_n(x = lubridate::today())

Arguments

x

a Date object or string, in the form of 'yyyy-mm-dd'

Value

ISO year in numeric

Examples

date_to_isoyear_n("2021-08-11")
#> [1] 2021
date_to_isoyear_n(lubridate::today())
#> [1] 2023